Is there a way to save the .par file with the best median cost rather than one with the best minimum cost for the distribution?

Hi, Your python code converts input coordinates and velocities to radians from degrees, but the Matlab code doesn't. If you change lines 35 - 38 to - for i=1:nCoordinates q2(:,i) = q.(nameCoordinates{i})(timeBool)*2*pi/180; u2(:,i) = u.(nameCoordinates{i})(timeBool)*2*pi/180; end then the Matlab cod...