fidadenx: Robertson kinetics DAE serial exampleproblem for IDA
          Three equation chemicalkinetics problem.

Tolerance parameters:  rtol = 0.10E-03   atol =  0.10E-05 0.10E-09 0.10E-05
Initial conditions y0 = ( 0.10E+01 0.00E+00 0.00E+00)

  t            y1           y2           y3        nst  k    h
0.2640E+00   0.9900E+00   0.3471E-04   0.1000E-01   75  2  0.5716E-01
     Above is a root, INFO() =   0  1
0.4000E+00   0.9852E+00   0.3386E-04   0.1480E-01   77  3  0.1143E+00
0.4000E+01   0.9055E+00   0.2240E-04   0.9447E-01   91  4  0.3704E+00
0.4000E+02   0.7158E+00   0.9185E-05   0.2842E+00  127  4  0.2963E+01
0.4000E+03   0.4505E+00   0.3223E-05   0.5495E+00  177  3  0.1241E+02
0.4000E+04   0.1832E+00   0.8940E-06   0.8168E+00  228  3  0.2765E+03
0.4000E+05   0.3899E-01   0.1622E-06   0.9610E+00  278  5  0.2614E+04
0.4000E+06   0.4939E-02   0.1985E-07   0.9951E+00  324  5  0.2770E+05
0.4000E+07   0.5176E-03   0.2072E-08   0.9995E+00  355  4  0.3979E+06
0.2075E+08   0.1000E-03   0.4000E-09   0.9999E+00  374  4  0.1592E+07
     Above is a root, INFO() =   1  0
0.4000E+08   0.5191E-04   0.2076E-09   0.9999E+00  380  3  0.6366E+07
0.4000E+09   0.5882E-05   0.2353E-10   0.1000E+01  394  1  0.9167E+08
0.4000E+10   0.7054E-06   0.2822E-11   0.1000E+01  402  1  0.1467E+10
0.4000E+11  -0.7300E-06  -0.2920E-11   0.1000E+01  407  1  0.2347E+11

Final Run Statistics:

Number of steps                    = 407
Number of residual evaluations     = 557
Number of Jacobian evaluations     =  65
Number of nonlinear iterations     = 557
Number of error test failures      =   6
Number of nonlinear conv. failures =   0
Number of root function evals.     = 437