idadenx: Robertson kinetics DAE serial example problem for IDA
         Three equation chemical kinetics problem.

Linear solver: IDADENSE, with user-supplied Jacobian.
Tolerance parameters:  rtol = 0.0001   atol = 1e-08 1e-14 1e-06 
Initial conditions y0 = (1 0 0)
Constraints and id not used.

-----------------------------------------------------------------------
  t             y1           y2           y3      | nst  k      h
-----------------------------------------------------------------------
2.6403e-01   9.8997e-01   3.4706e-05   1.0000e-02 |  85  2   6.4537e-02
    rootsfound[] =   0   1
4.0000e-01   9.8517e-01   3.3864e-05   1.4796e-02 |  88  2   6.4537e-02
4.0000e+00   9.0550e-01   2.2403e-05   9.4473e-02 | 102  4   4.1426e-01
4.0000e+01   7.1582e-01   9.1851e-06   2.8417e-01 | 136  2   1.3422e+00
4.0000e+02   4.5049e-01   3.2226e-06   5.4950e-01 | 190  4   3.3557e+01
4.0000e+03   1.8321e-01   8.9429e-07   8.1679e-01 | 239  4   3.4533e+02
4.0000e+04   3.8984e-02   1.6218e-07   9.6102e-01 | 287  5   2.0140e+03
4.0000e+05   4.9389e-03   1.9852e-08   9.9506e-01 | 339  3   1.6788e+04
4.0000e+06   5.1683e-04   2.0684e-09   9.9948e-01 | 444  4   2.1755e+05
2.0793e+07   1.0000e-04   4.0004e-10   9.9990e-01 | 495  4   1.0146e+06
    rootsfound[] =   1   0
4.0000e+07   5.2036e-05   2.0816e-10   9.9995e-01 | 506  5   2.5503e+06
4.0000e+08   5.2103e-06   2.0841e-11   9.9999e-01 | 541  4   2.3847e+07
4.0000e+09   5.2125e-07   2.0850e-12   1.0000e-00 | 569  4   3.9351e+08
4.0000e+10   5.1091e-08   2.0437e-13   1.0000e-00 | 589  2   6.0246e+09

Final Run Statistics: 

Number of steps                    = 589
Number of residual evaluations     = 832
Number of Jacobian evaluations     = 79
Number of nonlinear iterations     = 832
Number of error test failures      = 14
Number of nonlinear conv. failures = 0
Number of root fn. evaluations     = 617